initial array in size by ref c++

Question

I was asked to create this function:

int * createAndInput(int & size)

The function initializes an array in the size of the value size, gets the values from the user as input, and returns the allocated array and the size by ref.

Here is the code I have so far:

int *creatAndInput(int& size)
{ 
    int arr1[***size***];
    for (int i = 0; i << size; i++)
    {
        cout << "enter index " << (i + 1) << endl;
        cin >> arr1[i]; 
    }
    return (arr1);
}

void main()
{
    cout << "enter size number" << endl;
    int size2 = 10;
    int *size1 = &size2;
    cout << *creatAndInput(size2);
}

Please post your code directly in the question but not as image. — nayab, Oct 30 '21 at 19:37
You need to use `new[]` to allocate the array, or use `std::vector` instead. — Remy Lebeau, Oct 30 '21 at 22:22

score 0 · Answer 1 · edited Oct 30 '21 at 22:24

#include <iostream>

int* createAndInput(int& size)
{
    int* ptr = new int[size];

    for(int i = 0; i < size; i++){
        std::cout << i+1 << ". element: ";
        std::cin >> ptr[i];
    }

    return ptr;
}

int main(){

    int *ptr, size;

    std::cout << "Size: ";
    std::cin >> size;

    ptr = createAndInput(size);

    for(int i = 0; i < size; i++)
        std::cout << i+1 << ". element: "<< ptr[i] << std::endl;

    delete[] ptr;

    return 0;
}

initial array in size by ref c++

1 Answers1