Why does the "locals" function in Python output a global variable?

Question

y=3
class A:
    x = 1
    print(locals())
    print()
    print(globals())
print(globals())
print()
print(locals())

Why does the last line for locals() include the variable y even if it is global?

You're not in a function, so there is no local scope. `locals()` is `globals()` — khelwood, Jul 09 '20 at 15:16
There's no *distinct* local scope. "Local" is a relative term. — chepner, Jul 09 '20 at 15:17

score 4 · Answer 1 · answered Jul 09 '20 at 15:15

4

Note that at the module level, locals() and globals() are the same dictionary.

answered Jul 09 '20 at 15:15

chepner

1 Answers1