How come the first condition is false and the second is true? I was sure they were both true.
System.out.println(Integer.toString(3) == "3");
System.out.println(Integer.parseInt("3") == 3);
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2Don't compare reference types like `String` with `==`. `System.out.println(Integer.toString(3).equals("3"));` – Elliott Frisch Jul 08 '20 at 22:57
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Integer.parseInt converts a String to a primitive int and primitives can be compared with ==. However, Integer.toString produces a String object and == for objects checks that they are the exact same reference; use String#equals instead to compare the values of the Strings.
System.out.println(Integer.toString(3).equals("3"));
System.out.println(Integer.parseInt("3") == 3);
The above code outputs:
true
true
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