Need Regex to validate 11-digit phone number without plus sign

Question

I need a regex to validate phone number without plus (+) sign for example

46123456789,46-123-456-789,46-123-456-789

number should be 11 digit rest of should ignore

i am currently using this Regex /([+]?\d{1,2}[.-\s]?)?(\d{3}[.-]?){2}\d{4}/g

its not correct at all

Why not just remove the non-digit characters from the string then validate what's left is 11 characters long — Rory McCrossan, May 07 '20 at 13:34
Like `^\d{2}-\d{3}-\d{3}-\d{3}|\d{11}$` https://regex101.com/r/Ed4qJJ/1 This page has more info on validating phonenumbers https://stackoverflow.com/questions/123559/how-to-validate-phone-numbers-using-regex — The fourth bird, May 07 '20 at 13:42
You can use `/^[+]?(\d[^\d]*){11}$/g` http://refiddle.com/refiddles/5eb4109275622d7659040000 — freedomn-m, May 07 '20 at 13:46
@Thefourthbird i didnt need "+" sign your regex is fine but its allowing plus (+) sign — Umer Zaman, May 07 '20 at 14:37
@UmerZaman I don't think it is allowing a + sign due to the anchors `^` and `$` See https://regex101.com/r/Jhtnq5/1 — The fourth bird, May 07 '20 at 14:39
@Thefourthbird its allowing in this case "+46123456789" not for this "+46-123-456-789" — Umer Zaman, May 07 '20 at 14:42
@UmerZaman You are right, I am sorry I forgot the grouping around it `^(?:\d{2}-\d{3}-\d{3}-\d{3}|\d{11})$` https://regex101.com/r/E1VGfK/1 — The fourth bird, May 07 '20 at 14:43
@Thefourthbird thanks buddy that's correct can you post in answer ? — Umer Zaman, May 07 '20 at 14:46

score 1 · Accepted Answer · answered May 07 '20 at 15:00

About the pattern you tried:

Using this part in your pattern [+]? optionally matches a plus sign. It is wrapped in an optional group ([+]?\d{1,2}[.-\s]?)? possibly also matching 12 digits in total.

The character class [.-\s] matches 1 of the listed characters, allowing for mixed delimiters like 333-333.3333

You are not using anchors, and can also possible get partial matches.

You could use an alternation | to match either the pattern with the hyphens and digits or match only 11 digits.

^(?:\d{2}-\d{3}-\d{3}-\d{3}|\d{11})$

^ Start of string
(?: Non capture group for the alternation
- \d{2}-\d{3}-\d{3}-\d{3} Match either the number of digits separated by a hyphen
- | Or
- \d{11} Match 11 digits
) Close group
$ End of string.

Regex demo

If you want multiple delimiters which have to be consistent, you could use a capturing group with a backreference \1

^(?:\d{2}([-.])\d{3}\1\d{3}\1\d{3}|\d{11})$

Regex demo

Johan Syah · Answer 2 · 2020-05-07T14:08:24.513

0

I am not sure how is the input looks like. But based on your question I supposed you want to trim it and match it with regex?

trim your input.

string.split(/[^0-9.]/).join('');

and you can match it with this regex:

((\([0-9]{3}\))|[0-9]{3})[\s\-]?[\0-9]{3}[\s\-]?[0-9]{4}$

edited May 07 '20 at 14:08

answered May 07 '20 at 13:55

Johan Syah

21
4

score 0 · Answer 3 · answered May 07 '20 at 14:00

I would have this function return true or false and use as is.

function isPhoneValid(phone) {
  let onlyNumbers = phone.replace(/[^0-9]/g, "");
  if (onlyNumbers.length != 11) console.log(phone + ' is invalid');
  else console.log(phone + ' is valid');
}

isPhoneValid('1 (888) 555-1234');
isPhoneValid('(888) 555-1234');

Need Regex to validate 11-digit phone number without plus sign

3 Answers3