I am making a menu and submenus using recursion function and I am in the need of help to open only the respective menu and sub menu's..
For button and collapse Reactstrap has been used..
Recursive function that did menu population:
{this.state.menuItems &&
this.state.menuItems.map((item, index) => {
return (
<div key={item.id}>
<Button onClick={this.toggle.bind(this)}> {item.name} </Button>
<Collapse isOpen={this.state.isToggleOpen}>
{this.buildMenu(item.children)}
</Collapse>
</div>
);
})}
And the buildMenu function as follows,
buildMenu(items) {
return (
<ul>
{items &&
items.map(item => (
<li key={item.id}>
<div>
{this.state.isToggleOpen}
<Button onClick={this.toggle.bind(this)}> {item.name} </Button>
<Collapse isOpen={this.state.isToggleOpen}>
{item.children && item.children.length > 0
? this.buildMenu(item.children)
: null}
</Collapse>
</div>
</li>
))}
</ul>
);
}
There is no problem with the code as of now but I am in the need of help to make menu -> submenu -> submenu step by step open and closing respective levels.
Working example: https://codesandbox.io/s/reactstrap-accordion-9epsp
You can take a look at this example that when you click on any menu the whole level of menus gets opened instead of clicked one..
Requirement
If user clicked on menu One, then the submenu (children)
-> One-One
needs to get opened.
And then if user clicked on One-One,
-> One-One-One
-> One - one - two
-> One - one - three
needs to get opened.
Likewise it is nested so after click on any menu/ children their respective next level needs to get opened.
I am new in react and reactstrap way of design , So any help from expertise would be useful for me to proceed and learn how actually it needs to be done.