JS setTimeout Not Delayed

Question

I'm trying to put a delay in front of an AJAX call.

var delay = 2000;

$("#c_name").on("keyup", function() {
  var entered = $(this).val();
  if (entered.length > 1) { 
    setTimeout(dosearch(entered), delay) 
    }
  });

Fo some reason I can't seem to get setTimeout to take hold. It's performing the dosearch() function instantly.

How can I get this to delay properly? Yes JQuery 3.3.1 is loaded up top.

because you call it and assign what it returns to the timeout.... — epascarello, Mar 19 '19 at 17:48
No, it's not a duplicate. Read the answer to that question. "No parentheses" is not the answer. — Rich_F, Mar 19 '19 at 17:48
You can either wrap the function or add the parameters after the `delay` parameter: `setTimeout(dosearch, delay, entered)` https://developer.mozilla.org/en-US/docs/Web/API/WindowOrWorkerGlobalScope/setTimeout#Parameters — adiga, Mar 19 '19 at 17:49
`dosearch(entered)` is a function call. It is evaluated *before* `setTimeout()` is invoked. — Pointy, Mar 19 '19 at 17:50
I'm under the impression that `dosearch(entered)` is performed after. How can I delay that using `setTimeout(function, delay)`? — Rich_F, Mar 19 '19 at 17:51
Again, read all the answers to the duplicate. https://stackoverflow.com/a/7137443/1586174 — Taplar, Mar 19 '19 at 17:51
Wrap `dosearch(entered)` in a function: `function() { dosearch(entered); }` — Pointy, Mar 19 '19 at 17:51

score -1 · Answer 1 · answered Mar 19 '19 at 17:54

-1

Answer: Both of these work:

setTimeout(() => dosearch(entered), delay) 

setTimeout( function() { dosearch(entered) }, delay)

answered Mar 19 '19 at 17:54

Rich_F

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JS setTimeout Not Delayed

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