Why object method is rewrites the original objects?

Asked May 01 '18 at 10:34

Active May 01 '18 at 10:36

Viewed 27 times

Why when we rewrite the value of the method foo of the nested object s it's also rewrites the original object z method foo?

Explaine someone, please why it does and how to prevent it from rewrite?

const z = { foo: 'bar' };
const s = z;
s.foo = 'baz'; 
s == z // true

edited May 01 '18 at 10:36

asked May 01 '18 at 10:34

Max Wolfen

1

Because both `s` and `z` are referencing to the same object – Hassan Imam May 01 '18 at 10:35
@HassanImam thank you! But how we can prevent that from rewrite the original obj? – Max Wolfen May 01 '18 at 10:37
1

Try cloning the object using spread syntax or `Object.assign()`. – Hassan Imam May 01 '18 at 10:38
1

... `const s = {...z};` – Jonas Wilms May 01 '18 at 10:48

0 Answers0