grouping a dictionary by equal values

Question

Maybe a very common and easy question in here... my purpose is that grouping a dictionary according to its values for example;

D = {"k1":1,"k2":2,"k3":1,"k4":0,"k5":1,"k6":0}

output look like

part1=[0,[k4,k6]] part2=[1,[k1,k3,k5]] part3=[2,[k2]]

What have you tried, and why hasn't it worked for you? – cs95 Dec 17 '17 at 20:15 — cs95, Dec 17 '17 at 20:15

score 1 · Answer 1 · answered Dec 17 '17 at 20:23

def filter_by_value(dictionary, value):
    return [value, [i for i in dictionary if dictionary[i] == value]]

And if you want to do it with all the values the dictionary has you can just do:

def group_by_values(dictionary):
    #set ensures there are no repeated values
    return [filter_by_value(dictionary, i) for i in set(dictionary.values())]

Last but not least, if you want the list to be sorted just add a sorting function after the set:

def group_by_values(dictionary):
    #set ensures there are no repeated values
    return [filter_by_value(dictionary, i) for i in sorted(set(dictionary.values()))]

thank you so much Yadkee, one small step for you but one big step for me:) — HAKAN KÜÇÜK, Dec 17 '17 at 21:57

grouping a dictionary by equal values

1 Answers1