ErrorException' with message 'Undefined offset: 1

Question

I have an array that have an index 0 and index 1 and in some cases the index 1 will not be exist. I want to bypass it and pass only the index 0 or i want to create it and add value to it.

$eq = explode("  -  ", $div->textContent) ;
$p_part_one_name = $eq[0] ;
$p_part_two_name = $eq[1] ;

Answer 1

You should check if $eq[index] exists or not before sets it as a variable

$eq = explode("  -  ", $div->textContent) ;
if(isset($eq[0]))
    $p_part_one_name = $eq[0] ;
if(isset($eq[1]))
    $p_part_two_name = $eq[1] ;

Answer 2

HI you can use foreach

foreach ($arr as &$eq) {
   #Here your array value
}

you can check count of array

$result = count($eq );
if($result==2){
    $p_part_one_name = $eq[0] ;
    $p_part_two_name = $eq[1] ;
 }
else{
   $p_part_one_name = $eq[0] ;
}

Answer 3

You should try this:

The array_key_exists() function checks an array for a specified key, and returns true if the key exists and false if the key does not exist.

$eq = explode("  -  ", $div->textContent) ;

if (array_key_exists(1, $eq)) {
    $p_part_one_name = $eq[0] ;
    $p_part_two_name = $eq[1] ;
} else {
    $p_part_one_name = $eq[0] ;
}