Javascript str.replace with regex with double searchvalue

Question

This code

var i = '[0]';
i.replace(/\[|\]/, '');

returns i = '0]'

I want to use .replace function to converti = '0';

it works:) please post an answer, so I can choose you. Does it mean that without 'g' it just finds the first match only? — Sergej Fomin, Jul 26 '17 at 10:30
It finds the first occurence of `/\[|\]/`, which is `[`. I generally won’t post answers without searching for duplicate targets first. — Sebastian Simon, Jul 26 '17 at 10:31
`var i = '[0]'; i.replace(/\[|\]/g, '');` will output '0' I just added if somebody becomes confused about where to add 'g' flag. — user2906838, Jul 26 '17 at 10:33

score 1 · Answer 1 · answered Jul 26 '17 at 10:34

1

edit the code and use g flag

var i = '[0]';
i.replace(/\[|\]/g, '');

answered Jul 26 '17 at 10:34

Feras Al Sous

1 Answers1