ValueError: invalid literal for int() with base 10: ''

Question

I'm new in Python 3 and need some help, my error is:

"ValueError: invalid literal for int() with base 10: ''  "

any ideas? The code I'm using is the following:

liste = [1, 2, 3]

def liste_pop():
    print(liste)
    pop = int(input('remove = Enter um das letzte Element der Liste auszugeben + entfernen oder die Position eingeben'))
    liste.pop(pop)
    return

You did not enter a number during `input`, instead you simply pressed enter (and got back the empty string). Add code to handle the situation where a user enters invalid input (`try-except` in a loop). — Dimitris Fasarakis Hilliard, Dec 17 '16 at 20:19
Possible duplicate of [ValueError: invalid literal for int() with base 10: 'stop'](http://stackoverflow.com/questions/16742432/valueerror-invalid-literal-for-int-with-base-10-stop) — MalloyDelacroix, Dec 17 '16 at 20:28
not sure this would count as a dup of that @MalloyDelacroix but the solution posted there definitely works for this question. — Tadhg McDonald-Jensen, Dec 17 '16 at 20:30
I'd agree with Tadhg, that's why I posted an answer (didn't find a good dupe target after posting the comment). Either way, I'll keep on looking for a bit and see if I can find anything better. — Dimitris Fasarakis Hilliard, Dec 17 '16 at 20:34

score 2 · Answer 1 · answered Dec 17 '16 at 20:30

You did not enter a number during input, instead you simply pressed enter (and got back the empty string). You need to add code to handle the situation where a user enters invalid input, in Python, this is performed with a try-except where you specify the error you're expecting ValueError in the except clause:

def liste_pop():
    print(liste)
    while True:
        try:
            pop = int(input('remove = Enter um das letzte Element der Liste auszugeben + entfernen oder die Position eingeben'))
            break
        except ValueError as e:
            print("Only numbers accepted")
    liste.pop(pop)

Of course, this has an additional issue, what if a user enters a number outside the accepted range? An IndexError is raised; you'll need another try-except for that (I'll let you handle it on your own.)

ValueError: invalid literal for int() with base 10: ''

1 Answers1