How to give alias for a function in c

Question

The problem is something like:

I have a function named ADD_TWO(int,int);, now in the program, I want to create its alias keeping the previous function untouched. Something like ADD_TWO_NUMBERS(int,int);. i.e if I call ADD_TWO_NUMBERS it should execute ADD_TWO.

I want to have an Alias for the function.

Why not create `ADD_TWO_NUMBERS` function, that will call `ADD_TWO`? — Ari0nhh, Dec 05 '16 at 07:01

score 0 · Answer 1 · answered Dec 05 '16 at 07:04

int ADD_TWO(int a, int b)
{
    return a+b;
}

int main()
{
    int (*ADD_TWO_NUMBERS)(int, int) = ADD_TWO;
    int result = ADD_TWO_NUMBERS(10, 12);  //or (*ADD_TWO_NUMBERS)(10, 12)
    cout<<"  Result :- "<<result<<endl;
    return 0;
}

Use Function pointers

score 0 · Answer 2 · answered Dec 05 '16 at 07:11

0

Aside from using function pointers you can use function-like macros. Try something like

#define ADD_TWO_NUMBERS(x,y) ADD_TWO(x,y)

answered Dec 05 '16 at 07:11

Jawn Doe

21
5

Function pointers are better since they can be given a scope. – Lundin Dec 05 '16 at 07:36
Yeah. Nothing worse than a macro with bad breath. – user4581301 Dec 05 '16 at 07:41

score 0 · Answer 3 · answered Dec 05 '16 at 07:12

Since this question has c++ tag and assuming you're using a c++11 compiler, then:

int ADD_TWO(int a, int b)
{
    return a+b;
}

int main()
{
    auto ADD_TWO_NUMBERS = ADD_TWO;
    int result = ADD_TWO_NUMBERS(10, 12);
    cout << "  Result :- " << result << endl;
    return 0;
}

How to give alias for a function in c

3 Answers3