DisplayMemberPath not displaying Property - property not found in 'ViewModel'

Question

My MainView has a ViewModel called MainViewModel. MainViewModel creates a dialog and I want the dialogs ViewModel to be the already existing MainViewModel

To create the dialog from the MainViewModel I do

var MyInnerDlg = new MyInnerDlgView();
MyInnerDlg.DataContext = this;
MyInnerDlg.ShowDialog();

In the dialog I have a ListBox which I bind to a collection from my MainViewModel

public ObservableCollection<MyItemViewModel> MyList { get; set; }

XAML of the dialog

<Border Margin="5" BorderThickness="2">
    <ListBox ItemsSource="{Binding MyList}" DisplayMemberPath="{Binding MyList.Name}" />
</Border>

The Name property is in MyItemViewModel. With the above code I get the error:

Name property not found in MainViewModel.

How can I refer to each of the items Name property?

Yes it does. The error should not refer to the mainviewmodel even if it was not. Is this something to do with datacontext being 'this'? — user2837961, May 06 '16 at 11:34
I am using VS2013. The output window always refers parent VM ie mainviewmodel and not MyItemViewModel. That is the whole problem — user2837961, May 06 '16 at 12:01
@Bijington I'm sorry, I just saw your suggestion, which I added as an answer.. If you'd like I can remove my answer and let you post it instead? — default, May 06 '16 at 12:10
I was able to replicate the behavior you are seeing when I did not remove the Binding. Remove the binding as Bijington suggested and it should work fine. If it's still not working, make sure that you rebuilt your program. — default, May 06 '16 at 12:18

score 2 · Answer 1 · edited May 23 '17 at 10:33

2

DisplayMemberPath should probably not be a Binding. Change it to the property name of the property that you want to display, i.e. "Name"

<ListBox ItemsSource="{Binding MyList}" DisplayMemberPath="Name" />

Also, a general suggestion is not to have public setters on lists, since you can get unindented behavior. Instead, use a backing field and remove the setter.

edited May 23 '17 at 10:33

Community

1
1

answered May 06 '16 at 12:05

default

11,485
9
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Developer · Answer 2 · 2016-05-06T11:45:04.117

0

Try changing :

 <ListBox ItemsSource="{Binding MyList}" DisplayMemberPath="{Binding MyList.Name}">

To:

 <ListBox ItemsSource="{Binding MyList}" DisplayMemberPath="{Binding Name}">

Or try adding:

 <Page.Resources>
    <local:MyItemViewModel x:Key="DataContext" />   
 </Page.Resources> 

 <ListBox DataContext="{StaticResource DataContext}" ItemsSource="{Binding MyList}" DisplayMemberPath="{Binding MyList.Name}"> </ListBox>

Usually i add a ViewModel in the xaml file itself.

 <Page.Datacontext>
    <local:MyItemViewModel/>   
 </Page.Datacontext>

edited May 06 '16 at 11:45

answered May 06 '16 at 11:32

Developer

59
7

Seems someone was faster with the same suggestion. – Developer May 06 '16 at 11:34
wouldn't that create a new ViewModel? It seems OP wants to refer to the already existing one. – default May 06 '16 at 11:56
oh ok. Didn't catch that one. – Developer May 06 '16 at 12:20

DisplayMemberPath not displaying Property - property not found in 'ViewModel'

2 Answers2