call self invoking function from outside body function

Question

So i have the following code:

(function init_chart(){
    // body function
})();

it's working as expected. but when i tried to call the init_chart() from outside the function, console said it is undefined. then i tried to add the following line inside init_chart() function:

window['init_chart'] = this;

now console said init_chart is not a function.

What made you think that `this` refers to the function? `this` never refers to the function itself, unless you explicitly set it so. — Felix Kling, Mar 15 '16 at 14:58
awesome thanks. jquery "told" me so :D...it's my fault, I have to learn more about JS. thanks again. — Dariel Pratama, Mar 15 '16 at 15:02

JCOC611 · Answer 1 · 2016-03-15T14:59:05.390

2

You are creating a named function expression function, so basically the function is not defined on the global scope. The easiest way to get around it is to do the following:

function init_chart(){
    // body function
};
init_chart();

edited Mar 15 '16 at 14:59

answered Mar 15 '16 at 14:56

JCOC611

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"Named anonymous function" is kind of an oxymoron. Surely you mean "named function expression", right? ;) – Scimonster Mar 15 '16 at 14:56
@Scimonster it's way too early in the morning haha – JCOC611 Mar 15 '16 at 14:59

call self invoking function from outside body function

1 Answers1