How size of the array is changing in the list?

Asked Feb 01 '16 at 08:05

Active Feb 01 '16 at 13:15

Viewed 38 times

After adding a new index, the size of the array is changed from n to n+1. I have declared my array with size of n. When I added a new index it is automatically changing its size from n to n+1?

main()
{
    int n=5;
    int a[n];

    // input in array
    for (int i=0;i<n;i++)
    {
        cin>>a[i];
    }
    // add number at start
    n=n+1;
    int k=n-1;
    for (int i=k;i>0;i--)
    {
        a[i]=a[i-1];
    }
    a[0]=8;

edited Feb 01 '16 at 13:15

Qazazaz

asked Feb 01 '16 at 08:05

Dee Khan

int n=5; int a[n]; was this compiled?? – Humam Helfawi Feb 01 '16 at 08:06
3

There is no size adjustment going on. You simply have a bug. – juanchopanza Feb 01 '16 at 08:07
I am guessing you're asking about out of bounds access, but it is difficult to know for sure. So if you're asking about something else, please clarify your question. – juanchopanza Feb 01 '16 at 08:09
2

@juanchopanza When I run this code I am not getting any error at all. if there is some error then definitely I will ask about that.. but this error free code compiled and run in Dev C++ – Dee Khan Feb 01 '16 at 09:27
1

@juanchopanza I am asking about the size of `a[n]`. in the start I have declared that size of `a[n]` and when insert new element in the list at start then compiler itself changed the size of `a[n]` to `a[n+1]`? – Dee Khan Feb 01 '16 at 09:29
OK, then the duplicate covers it. – juanchopanza Feb 01 '16 at 09:37
@juanchopanza I have checked the duplicate question it was using gcc but I am not using that – Dee Khan Feb 01 '16 at 09:38
@DeeKhan It doesn't matter. It is undefined behaviour. – juanchopanza Feb 01 '16 at 09:48
as I am not getting any error, so the undefined behavior is not error actually, right? – Dee Khan Feb 01 '16 at 09:54

How size of the array is changing in the list?

0 Answers0