Correctly way to declare var with another var PHP

Question

I need a way to declare a variable to use in while loop like this:

$x = 1;
    while ($x < 5){
    echo $row['img$x'];
    $x++;
}

In my case, this returned a syntax error.

basic php 101: `'`-quoted strings do **NOT** interpolate variables. you have a literal `$` and `x` in your array key name. — Marc B, Jan 07 '16 at 20:11
If you're getting a syntax error, it's somewhere else. Your code is wrong, but it's valid PHP syntax. — Barmar, Jan 07 '16 at 20:14

score 2 · Answer 1 · answered Jan 07 '16 at 20:13

2

Two options:

$row['img' . $x]
// or
$row["img$x"]

Use double quotes "" if you want to use string interpolation and . for string concatenation.

answered Jan 07 '16 at 20:13

Jeroen Noten

1 Answers1