I'm using tuckey URL rewriting with JSF.
I would like to get the relative URL including parameters that the user sees: e.g.
example.com/mypage?param=test
At the moment if I do
#{view.viewId}
I get
mypage.xhtml
what I want to get is:
mypage?param=test
The UIViewRoot#getViewId() returns the JSF view ID. You need to use HttpServletRequest#getRequestURI() to obtain the current request URI and HttpServletRequest#getQueryString() to obtain the current request query string.
#{request.requestURI}#{empty request.queryString ? '' : '?'}#{request.queryString}
Or, if it's a forwarded request, get it as a request attribute keyed with RequestDispatcher.FORWARD_REQUEST_URI and RequestDispatcher.FORWARD_QUERY_STRING respectively:
#{requestScope['javax.servlet.forward.request_uri']}#{empty requestScope['javax.servlet.forward.query_string'] ? '' : '?'}#{requestScope['javax.servlet.forward.query_string']}
Clumsy yes. Consider hiding away in <c:set> of a master template, or an utility tag/function.
