How to convert a String consisting of Binary Number to Hexa Decimal no in Java?

Question

My String is 010101010111111111101010101010101010111101010101010101010101 and it is large in size (more than 64 characters).

I cannot use Integer or Long class parse methods due to size limitation.

Expected Output would be 557FEAAAAF55555h.

my bad its BigInteger, more used to JS so, made this mistake — prasun, Oct 10 '15 at 04:47

score 2 · Answer 1 · edited May 23 '17 at 11:58

2

I don't know your performance requirements, but it seems to me you could simply:

Split your string into nibbles of 4 (see Splitting a string at every n-th character);
Then convert each of them into an integer (see Converting String to Int in Java?);
And finally and concatenate their hexadecimal value (see Java.lang.Integer.toHexString() Method).

edited May 23 '17 at 11:58

Community

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answered Oct 10 '15 at 04:53

InfectedPacket

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This is a good approach, but you have to handle the case where the input string isn't a multiple of 4. – ajb Oct 10 '15 at 05:05
Agreed. You could still use the length of the string, modulo 4 and use the result as the number of "0" to prefix the string (if it's not a stream). However `BigInteger` is much more elegant and faster. – InfectedPacket Oct 10 '15 at 05:13

score 1 · Accepted Answer · answered Oct 10 '15 at 05:15

Use BigInteger for this:

String s = "010101010111111111101010101010101010111101010101010101010101";
BigInteger value = new BigInteger(s, 2);
System.out.println(value.toString(16));

This shows:

557feaaaaf55555

Or to get your exact output:

System.out.println(value.toString(16).toUpperCase() + "h");

score 0 · Answer 3 · answered Oct 10 '15 at 05:22

   public  String GetHex(String binary){
        String[] parts=binary.split("(?<=\\G.{4})");
        String output="";
        for(String s: parts)
        {
            output+=Integer.toHexString(Integer.parseInt(s, 2));
        }
    }

And Call it with your Binary String

 String binary="010101010111111111101010101010101010111101010101010101010101";
     String hexvalue=GetHex(binary); //557feaaaaf55555

How to convert a String consisting of Binary Number to Hexa Decimal no in Java?

3 Answers3