Why `return` doesn't interrupt the function?

Question

When I call in console foo(), it returns 4.

function foo()
{
    function bar(){
        return 3;
    };

    return bar();

    function bar(){
        return 4;
    }
}

Does it mean that return only interrupts during execution not during declaration? Your explanations are invaluable.

[Function declaration hosting on MDN](https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Statements/function#Function_declaration_hoisting) — Ry-, Jul 28 '15 at 01:30
Thank you Daniel for the notion, Felix for the detail, and MDN for the examples in the good link — Adib Aroui, Jul 28 '15 at 01:36

score 0 · Accepted Answer · answered Jul 28 '15 at 01:29

0

It returns 4 because function declarations are parsed and assigned before everything else. It is not like var f = function () { ... };.

answered Jul 28 '15 at 01:29

Alex Netkachov

Yes this is it, function declaration hoisting. thank you waiting for timer to expire – Adib Aroui Jul 28 '15 at 01:36

1 Answers1