android.util.Patterns.EMAIL_ADDRESS is validating invalid emails

Question

These are few emails which are not valid.

email@domain.web
.email@domain.com

I have checked above emails in following websites, All of those returns invalid. http://isemail.info/about http://sqa.fyicenter.com/Online_Test_Tools/Email_Address_Format_Validator.php.

Yet, android.util.Patterns.EMAIL_ADDRESS pattern validates both.

Is there a bug or am I missing something?

The first one certainly looks fine, [as `.web` is an unofficial TLD](http://en.wikipedia.org/wiki/.web). The second one may be an issue. — CommonsWare, Apr 07 '15 at 13:03
Try this way hope this will help you, http://stackoverflow.com/questions/1819142/how-should-i-validate-an-e-mail-address — Silvans Solanki, Apr 07 '15 at 13:05
The second email is invalid - Character . (dot, period, full stop) (ASCII: 46) provided that it is not the first or last character, and provided also that it does not appear consecutively (e.g. John..Doe@example.com is not allowed). Source: http://en.wikipedia.org/wiki/Email_address — Bojan Kseneman, Apr 07 '15 at 13:34

score 6 · Answer 1 · edited Apr 29 '19 at 03:00

Please check you are using right condition means you use same if condition. because some times we use vice-versa. I know you are using the same thing but please check this method. I am sure it will be helpful for you.

/* returns true if the email is valid otherwise return false */

@SuppressLint("DefaultLocale")
public boolean checkForEmail(EditText edit, String editName) {
    String str = edit.getText().toString();
    if (android.util.Patterns.EMAIL_ADDRESS.matcher(str).matches()) {
        return true;
    }
    toastMsg(_context.getString(R.string.please_enter_valid).toString()+" "+editName+ " "
            );
    return false;
}

score 4 · Accepted Answer · edited Jan 07 '20 at 14:17

4

Both seems to be valid email addresses

email@domain.web
.email@domain.com

since any email address contains three components

<username>@<mail-server>.<mail-servertype or server-location>

Here android.util.Patterns.EMAIL_ADDRESS validates all the three components using regex and also checks if all three components are placed properly. Some common confusing examples are:

com@web123.com is a valid mail address since com can be a user name and web123 can be a web server's name.
.maths.apple@com.in is also a valid mail address since .maths.apple can be a user name and com can be a web server's name.

Invalid case:

crick@.web.com is invalid since a . cannot come before or after @. No mailing system will be able to recognize the username or mail-server name.

edited Jan 07 '20 at 14:17

Michael

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answered Apr 07 '15 at 13:32

Prathmesh Swaroop

611
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2

The local part ("user name" as you call it) cannot have a dot '.' at the start or the end of it unless it is in quotes. If Patterns.EMAIL_ADDRESS is saying `.email@domain.com` is valid, it is violating RFC rules: "period (".") may also appear, but may not be used to start or end the local part..." - https://tools.ietf.org/html/rfc3696 – Tom Aug 10 '16 at 21:23
android.util.Patterns.EMAIL_ADDRESS also accepts stuff like **test@t.t** which is definitely not a valid email address. Top level domain with only 1 letter is not possible. – Daniela Vladimirova Mar 13 '17 at 16:27
@DanielaVladimirova, One-letter TLDs are valid, they just don't exist yet. That could change at any time. See https://stackoverflow.com/questions/7411255/is-it-possible-to-have-one-single-character-top-level-domain-name – Samuel Bradshaw Sep 10 '18 at 21:00

score 1 · Answer 3 · answered Apr 07 '15 at 13:48

1

Well, the easiest way is to use the java Class InternetAddress instead of Android. Utils... or regex

answered Apr 07 '15 at 13:48

noah_abou

99
12

score -1 · Answer 4 · answered Apr 07 '15 at 13:03

Use regex matching with this pattern below.

String EMAIL_PATTERN = "^[_A-Za-z0-9-\\+]+(\\.[_A-Za-z0-9-]+)*@[A-Za-z0-9-]+(\\.[A-Za-z0-9]+)*(\\.[A-Za-z]{2,})$"


private Matcher matcher;
private Pattern pattern = Pattern.compile(EMAIL_PATTERN);


public boolean validateEmail(final String hex) {
    matcher = pattern.matcher(hex);
    return matcher.matches();
}

Hope this helps.

android.util.Patterns.EMAIL_ADDRESS is validating invalid emails

4 Answers4

Invalid case:

Linked