I have want to match files located in multiple directories:
The file path could be locally - C:/users/path/image.png or on a system - //home/user/web/image.png
For the first case, I have regular expression -
[c|C]:[^.]+[.][A-Za-z]{3}
How can I have a single regex to match both of the cases?
Try
((c|C|//home)[^.]+[.][A-Za-z]{3})
If you want to use findall(), all the matches will be presented in a list of tuples. The tuples contain the groups in the regex, and that's the crux of the regex above - the whole expression has to be a group itself to show up in the return value of findall(). See the following code
smth = "//home/user/web/image.png C:/users/path/image.png c:/web/image.png"
ip = re.findall("((c|C|//home)[^.]+[.][A-Za-z]{3})",smth)
print ip
[('//home/user/web/image.png', '//home'), ('C:/users/path/image.png', 'C'), ('c:/web/image.png', 'c')]
What you're trying to get from the match is not clear - maybe you just want the full string?
((?:(?:[cC]:)|//home)[^\.]+\.[A-Za-z]{3})
A dot (.) will match (close to) everything. If you want to compare and contrast against the string ., you should escape it with \..
Test runs:
>>> print re.match("((?:(?:[cC]:)|//home)[^\.]+\.[A-Za-z]{3})", "//home/user/web/image.png").groups()
('//home/user/web/image.png',)
>>> print re.match("((?:(?:[cC]:)|//home)[^\.]+\.[A-Za-z]{3})", "C:/users/path/image.png").groups()
('C:/users/path/image.png',)
And one for the usual Windows path syntax:
>>> print re.match("((?:(?:[cC]:)|//home)[^\.]+\.[A-Za-z]{3})", "C:\users\path\image.png").groups()
('C:\\users\\path\\image.png',)
If there's a need to support .jpeg, increase the max allowed occurrences for the extensions from {3} to {3,4}.
