print number vertically and grouping it

Question

I am trying to print number vertically and it must be in group

here is my code

$nums = 105;
$rows = 8;
$col = floor($nums / $rows);
$group = floor($col / 3);
$count = 0;
for ($g = 0; $g <= $group; $g++) {
    echo "<div class='group'>";
    for ($i = 1; $i <= $rows; $i++) {
        for ($j = $i; $j <= 24; $j = $j + $rows) {
            $count++;
            if($count>$nums){
                break;
        }
            echo "<div class='fleft'>$count</div>";
        }
        echo "<div class='clear'></div>";
    }
    echo "</div>";
}

out of above

enter image description here

but i want output like for the first column

enter image description here

and next group number will start from where first group number end. in this case next group start from 25

please ask if any doubt

i can do that if have to display in one group only but not able to do in groups — Bhavik Patel, Nov 08 '13 at 08:20
I hope this could help You: http://stackoverflow.com/questions/18844108/how-to-set-the-limit-to-display-records-in-table-cell-using-mysql-and-php/18844214#18844214 — Adam, Nov 08 '13 at 08:33
i made a soln by altering ur code .. hope that helps ...postng it.. — internals-in, Nov 08 '13 at 08:41

rNix · Accepted Answer · 2013-11-11T03:13:02.300

$nums = 105;
$rows = 8;
$colsize = 3;

$col = floor($nums / $rows);
$group = floor($col / $colsize);
$count = 0;
$groupsize = $rows * $colsize;
for ($g = 0; $g <= $group; $g++) {
    echo "<div class='group'>";

    $modulo = 0;
    $correction = 0;
    $rest = $nums - $count;
    if ($rest < $groupsize) {
        $empty = $groupsize - $rest;
        $correction = floor($empty / $colsize);
        $modulo = $empty % $colsize;
    }
    for ($i = 1; $i <= $rows; $i++) {
        $colind = 0;
        for ($j = $i; $j <= $groupsize; $j = $j + $rows) { 
            $count++;
            if ($count > $nums) {
                break;
            }
            $val = $j + ($g * $groupsize);

            $val -= $colind * $correction;
            $modcor = $colind - ($colsize - $modulo);
            if ( $modcor > 0 ) {
                $val -= $modcor;
            }
            echo "<div class='fleft'>" . $val . "</div>";
            $colind++;
        }
        echo "<div class='clear'></div>";
    }
    echo "</div>";
}

This works:

enter image description here

Also, you can change number of digits, columns or size of column

Problem with this : put $nums=31, 30 is missing and it should print up to 31. this is printing to 32. by the way this is good . i am voting up for logic — Bhavik Patel, Nov 08 '13 at 12:57

score 0 · Answer 2 · answered Nov 08 '13 at 08:30

0

for($group = 0; $group < 3; $group++){
    for($row =1 ; $row <= 8; $row++){
        for($col = 0; $col <= 2; $col++){
            echo ($group*24)+ $row + 8 * $col; echo " ";
        }
        echo "\n";
    }
}

This code will print the number in the requested format. You need to modify according to your need.

answered Nov 08 '13 at 08:30

Gaurav

28,447
8
50
80

this is not printing up to number (105) – Bhavik Patel Nov 08 '13 at 08:56
1

This code won't print the number exactly you want. You need to change the code according to your need. I have given you the logic of printing numbers in group of 8*3 – Gaurav Nov 08 '13 at 09:49

internals-in · Answer 3 · 2013-11-08T08:43:34.950

0

may be i am mad , made a simple alter .... try this

$nums = 105;
$rows = 8;
$col = floor($nums / $rows);
$group = floor($col / 3);
$count = 0;
$letCounter=0;  //added a counter

for ($g = 0; $g <= $group; $g++) {

    echo "<div class='group'>";
    for ($i = 1; $i <= $rows; $i++) {
        $letCounter=0; //reset counter on each loop
        for ($j = $i; $j <= 24; $j = $j + $rows) 
        {
         $count++;
         if($count>$nums)
         {break;}
        //made an alter  in the below line , some math :)
         echo "<div class='fleft'>".($letCounter++ * $rows +$i)."</div>";  
        }
        echo "<div class='clear'></div>";
    }
    echo "</div>";
}

Thanks !

edited Nov 08 '13 at 08:43

answered Nov 08 '13 at 08:35

internals-in

4,798
2
21
38

@BhavikPatel yep....any problm wth u? 1 9 17 2 10 18 3 11 19 4 12 20 5 13 21 6 14 22 7 15 23 8 16 24 1 9 17 2 10 18 3 11 – internals-in Nov 08 '13 at 13:27
it's repeating not increasing after 24 – Bhavik Patel Nov 09 '13 at 10:05

score 0 · Answer 4 · answered Nov 08 '13 at 09:27

This May work

$nums = 105;
$rows = 8;
$col = floor($nums / $rows);
$group = floor($col / 3);
$count = 0;
$flag = true;
for($c=1;$c<=$col;$c++)
{

        if($c%$group== 1)
        {
            echo "Group Start";
            $flag = false;
        }
        for ($i = 1; $i <= $rows; $i++) {
                $count++;
                echo "<div class='fleft'>$count</div>";

            echo "<div class='clear'></div>";

        }
        echo "Line End";
        if($c%$group == 2&& $flag)// Check here for your requirement        
            echo "Group End </br>";
        $flag = true;

}

print number vertically and grouping it

4 Answers4